Generate multiple files using each line of a file in Linux

ISSUE:

Sometimes a file or a command need be used against to a list of servers or databases. So a general file or command need be generated with specific information as a general pattern such as database name.

SOLUTION:

A simple While statement can do this task.  So general while statement is provided for easy access

Statement:

while read line
do
host_name=`echo $line | cut -d ' ' -f 1` #get first field of input line
host_ip=`echo $line | cut -d ' ' -f 2`       # get second field of input line
short_hname=${host_name%%\.*}      # remove domain port of hostname
alias_hname=${short_hname:9:5}        # extract 5 character starting at 9 as alias name
if [ ${short_hname:0:3} == "tet" ] ; then # extract 3 character to setup environment name
env_name=test
else
env_name=${short_hname:4:3}
fi
echo "sshpass -e ssh -o StrictHostKeyChecking=no test@$host_ip" > ${env_name}_${alias_hname}_${short_hname}.sh  # generate a sh file for ssh login for each server
chmod 700 ${env_name}_${alias_hname}_${short_hname}.sh # make gererated file executable
done < serverlist.txt

Xlib: Client is not authorized to connect to Server Exceed

ISSUE:

Remote display is refused by local exceed server.

Cause:

host acceptence ACL is not configured for the remote server.

Solution:

configure exceed to accept anyhost or the remote servers you want

1.  click Start -> all program -> Hummingbird Connectivity 2008 x64 -> exceed tools -> Xconfig

2. click icon "Security, Access Control and System Administration" category.

3. select file if you need input a list of servers or any host access for all hosts

4. save and exit